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(X-5)X=3300
We move all terms to the left:
(X-5)X-(3300)=0
We multiply parentheses
X^2-5X-3300=0
a = 1; b = -5; c = -3300;
Δ = b2-4ac
Δ = -52-4·1·(-3300)
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13225}=115$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-115}{2*1}=\frac{-110}{2} =-55 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+115}{2*1}=\frac{120}{2} =60 $
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