(X-6)-2-5x=3(2x-5)+10-5x

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Solution for (X-6)-2-5x=3(2x-5)+10-5x equation: 



(X-6)-2-5X=3(2X-5)+10-5X

We move all terms to the left:

(X-6)-2-5X-(3(2X-5)+10-5X)=0

We add all the numbers together, and all the variables

-5X+(X-6)-(3(2X-5)+10-5X)-2=0

We get rid of parentheses

-5X+X-(3(2X-5)+10-5X)-6-2=0



We calculate terms in parentheses: -(3(2X-5)+10-5X), so:

3(2X-5)+10-5X

determiningTheFunctionDomain
3(2X-5)-5X+10

We add all the numbers together, and all the variables

-5X+3(2X-5)+10

We multiply parentheses

-5X+6X-15+10

We add all the numbers together, and all the variables

X-5

Back to the equation:

-(X-5)



We add all the numbers together, and all the variables

-4X-(X-5)-8=0

We get rid of parentheses

-4X-X+5-8=0

We add all the numbers together, and all the variables

-5X-3=0

We move all terms containing X to the left, all other terms to the right

-5X=3

X=3/-5

X=-3/5

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