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(X-6)/(3X)+1=(X+5)/(X)
We move all terms to the left:
(X-6)/(3X)+1-((X+5)/(X))=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
Domain of the equation: X)!=0We calculate fractions
X!=0/1
X!=0
X∈R
(X-6)*X)/3X^2+(-((X+5)*3X)/3X^2+1=0
We calculate fractions
((X-6)*X)*3X^2)/(3X^2+(*3X^2)+(-((X+5)*3X)*3X^2)/(3X^2+(*3X^2)+1=0
We get rid of parentheses
((X-6)*X)*3X^2)/(3X^2+*3X^2+(-((X+5)*3X)*3X^2)/(3X^2+(*3X^2)+1=0
We calculate fractions
*3X^2+(((X-6)*X)*3X^2)*(3X^2+*3X^2+1)/((3X^2*(3X^2+(*3X^2)+1)+((-((X+5)*3X)*3X^2)*3X^2/((3X^2*(3X^2+(*3X^2)+1)=0
We calculate terms in parentheses: +(((X-6)*X)*3X^2)*(3X^2+*3X^2+1)/((3X^2*(3X^2+(*3X^2)+1)+((-((X+5)*3X)*3X^2)*3X^2/((3X^2*(3X^2+(*3X^2)+1), so:
((X-6)*X)*3X^2)*(3X^2+*3X^2+1)/((3X^2*(3X^2+(*3X^2)+1)+((-((X+5)*3X)*3X^2)*3X^2/((3X^2*(3X^2+(*3X^2)+1
We can not solve this equation
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