(X-7)(x-7)-(1+x)(1+x)=2(3x-4)

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Solution for (X-7)(x-7)-(1+x)(1+x)=2(3x-4) equation: 



(X-7)(X-7)-(1+X)(1+X)=2(3X-4)

We move all terms to the left:

(X-7)(X-7)-(1+X)(1+X)-(2(3X-4))=0

We add all the numbers together, and all the variables

(X-7)(X-7)-(X+1)(X+1)-(2(3X-4))=0

We multiply parentheses ..

(+X^2-7X-7X+49)-(X+1)(X+1)-(2(3X-4))=0



We calculate terms in parentheses: -(2(3X-4)), so:

2(3X-4)

We multiply parentheses

6X-8

Back to the equation:

-(6X-8)



We get rid of parentheses

X^2-7X-7X-(X+1)(X+1)-6X+49+8=0

We multiply parentheses ..

X^2-(+X^2+X+X+1)-7X-7X-6X+49+8=0

We add all the numbers together, and all the variables

X^2-(+X^2+X+X+1)-20X+57=0

We get rid of parentheses

X^2-X^2-X-X-20X-1+57=0

We add all the numbers together, and all the variables

-22X+56=0

We move all terms containing X to the left, all other terms to the right

-22X=-56

X=-56/-22

X=2+6/11

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