(X-7)(x-7)=(x+1)(x+1)

Solution for (X-7)(x-7)=(x+1)(x+1) equation:

(X-7)(X-7)=(X+1)(X+1)

We move all terms to the left:

(X-7)(X-7)-((X+1)(X+1))=0

We multiply parentheses ..

(+X^2-7X-7X+49)-((X+1)(X+1))=0


We calculate terms in parentheses: -((X+1)(X+1)), so:

(X+1)(X+1)

We multiply parentheses ..

(+X^2+X+X+1)

We get rid of parentheses

X^2+X+X+1

We add all the numbers together, and all the variables

X^2+2X+1

Back to the equation:

-(X^2+2X+1)


We get rid of parentheses

X^2-X^2-7X-7X-2X+49-1=0

We add all the numbers together, and all the variables

-16X+48=0

We move all terms containing X to the left, all other terms to the right

-16X=-48

X=-48/-16

X=+3