(X-7)(x-8)=(x-5)(x-4)

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Solution for (X-7)(x-8)=(x-5)(x-4) equation:



(X-7)(X-8)=(X-5)(X-4)
We move all terms to the left:
(X-7)(X-8)-((X-5)(X-4))=0
We multiply parentheses ..
(+X^2-8X-7X+56)-((X-5)(X-4))=0
We calculate terms in parentheses: -((X-5)(X-4)), so:
(X-5)(X-4)
We multiply parentheses ..
(+X^2-4X-5X+20)
We get rid of parentheses
X^2-4X-5X+20
We add all the numbers together, and all the variables
X^2-9X+20
Back to the equation:
-(X^2-9X+20)
We get rid of parentheses
X^2-X^2-8X-7X+9X+56-20=0
We add all the numbers together, and all the variables
-6X+36=0
We move all terms containing X to the left, all other terms to the right
-6X=-36
X=-36/-6
X=+6

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