(X-7)/3=1+(6x-5)/9

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Solution for (X-7)/3=1+(6x-5)/9 equation:



(X-7)/3=1+(6X-5)/9
We move all terms to the left:
(X-7)/3-(1+(6X-5)/9)=0
We calculate fractions
X/()+(-(1+(6X-5)*3)/()=0
We calculate terms in parentheses: +(-(1+(6X-5)*3)/(), so:
-(1+(6X-5)*3)/(
We multiply all the terms by the denominator
-(1+(6X-5)*3)
We calculate terms in parentheses: -(1+(6X-5)*3), so:
1+(6X-5)*3
determiningTheFunctionDomain (6X-5)*3+1
We multiply parentheses
18X-15+1
We add all the numbers together, and all the variables
18X-14
Back to the equation:
-(18X-14)
We get rid of parentheses
-18X+14
Back to the equation:
+(-18X+14)
We get rid of parentheses
X/()-18X+14=0
We multiply all the terms by the denominator
X-18X*()+14*()=0
We add all the numbers together, and all the variables
X-18X*()=0

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