(X-8)+x=x(2x-3)

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Solution for (X-8)+x=x(2x-3) equation: 



(X-8)+X=X(2X-3)

We move all terms to the left:

(X-8)+X-(X(2X-3))=0

We add all the numbers together, and all the variables

X+(X-8)-(X(2X-3))=0

We get rid of parentheses

X+X-(X(2X-3))-8=0



We calculate terms in parentheses: -(X(2X-3)), so:

X(2X-3)

We multiply parentheses

2X^2-3X

Back to the equation:

-(2X^2-3X)



We add all the numbers together, and all the variables

2X-(2X^2-3X)-8=0

We get rid of parentheses

-2X^2+2X+3X-8=0

We add all the numbers together, and all the variables

-2X^2+5X-8=0

a = -2; b = 5; c = -8;
Δ = b2-4ac
Δ = 52-4·(-2)·(-8)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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