(X-9)/6=(x+2)/7

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Solution for (X-9)/6=(x+2)/7 equation: 



(X-9)/6=(X+2)/7

We move all terms to the left:

(X-9)/6-((X+2)/7)=0

We calculate fractions


X/()+(-((X+2)*6)/()=0



We calculate terms in parentheses: +(-((X+2)*6)/(), so:

-((X+2)*6)/(

We multiply all the terms by the denominator


-((X+2)*6)



We calculate terms in parentheses: -((X+2)*6), so:

(X+2)*6

We multiply parentheses

6X+12

Back to the equation:

-(6X+12)



We get rid of parentheses

-6X-12

Back to the equation:

+(-6X-12)



We get rid of parentheses

X/()-6X-12=0

We multiply all the terms by the denominator


X-6X*()-12*()=0

We add all the numbers together, and all the variables

X-6X*()=0

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