(X/10)=(10/2x+21)

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Solution for (X/10)=(10/2x+21) equation:



(X/10)=(10/2X+21)
We move all terms to the left:
(X/10)-((10/2X+21))=0
Domain of the equation: 2X+21))!=0
X∈R
We add all the numbers together, and all the variables
(+X/10)-((10/2X+21))=0
We get rid of parentheses
X/10-((10/2X+21))=0
We calculate fractions
2X^2/20X+()/20X=0
We multiply all the terms by the denominator
2X^2+()=0
We add all the numbers together, and all the variables
2X^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{4}=0$

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