(X/10)=(10/2x+21)

Solution for (X/10)=(10/2x+21) equation:

(X/10)=(10/2X+21)

We move all terms to the left:

(X/10)-((10/2X+21))=0


Domain of the equation: 2X+21))!=0

X∈R


We add all the numbers together, and all the variables

(+X/10)-((10/2X+21))=0

We get rid of parentheses

X/10-((10/2X+21))=0

We calculate fractions


2X^2/20X+()/20X=0

We multiply all the terms by the denominator


2X^2+()=0

We add all the numbers together, and all the variables

2X^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{4}=0$