(X/3)+(x/4)+(x/5)=47

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Solution for (X/3)+(x/4)+(x/5)=47 equation: 



(X/3)+(X/4)+(X/5)=47

We move all terms to the left:

(X/3)+(X/4)+(X/5)-(47)=0

We add all the numbers together, and all the variables

(+X/3)+(+X/4)+(+X/5)-47=0

We get rid of parentheses

X/3+X/4+X/5-47=0

We calculate fractions

There is no solution for this equation

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