(X/5)+(x/6)=(11/30)

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Solution for (X/5)+(x/6)=(11/30) equation:



(X/5)+(X/6)=(11/30)
We move all terms to the left:
(X/5)+(X/6)-((11/30))=0
We add all the numbers together, and all the variables
(+X/5)+(+X/6)-((+11/30))=0
We get rid of parentheses
X/5+X/6-((+11/30))=0
We calculate fractions
540X^2/()+450X^2/()+()/()=0
We add all the numbers together, and all the variables
540X^2/()+450X^2/()+1=0
We multiply all the terms by the denominator
540X^2+450X^2+1*()=0
We add all the numbers together, and all the variables
990X^2=0
a = 990; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·990·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{1980}=0$

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