(X/5)+(x/6)=(11/30)

Solution for (X/5)+(x/6)=(11/30) equation:

(X/5)+(X/6)=(11/30)

We move all terms to the left:

(X/5)+(X/6)-((11/30))=0

We add all the numbers together, and all the variables

(+X/5)+(+X/6)-((+11/30))=0

We get rid of parentheses

X/5+X/6-((+11/30))=0

We calculate fractions


540X^2/()+450X^2/()+()/()=0

We add all the numbers together, and all the variables

540X^2/()+450X^2/()+1=0

We multiply all the terms by the denominator


540X^2+450X^2+1*()=0

We add all the numbers together, and all the variables

990X^2=0

a = 990; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·990·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{1980}=0$