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(X/9)=(12/3X)
We move all terms to the left:
(X/9)-((12/3X))=0
Domain of the equation: 3X))!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
(+X/9)-((+12/3X))=0
We get rid of parentheses
X/9-((+12/3X))=0
We calculate fractions
3X^2/27X+()/27X=0
We multiply all the terms by the denominator
3X^2+()=0
We add all the numbers together, and all the variables
3X^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{0}{6}=0$
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