(X2+2x-5)-(3x+2)=x2-1

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Solution for (X2+2x-5)-(3x+2)=x2-1 equation: 



(X2+2X-5)-(3X+2)=X2-1

We move all terms to the left:

(X2+2X-5)-(3X+2)-(X2-1)=0

We add all the numbers together, and all the variables

(+X^2+2X-5)-(+X^2-1)-(3X+2)=0

We get rid of parentheses

X^2-X^2+2X-3X-5+1-2=0

We add all the numbers together, and all the variables

-1X-6=0

We move all terms containing X to the left, all other terms to the right

-X=6

X=6/-1

X=-6

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