(X2-3x-10)(x2-5x-6x)=144

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Solution for (X2-3x-10)(x2-5x-6x)=144 equation: 



(X2-3X-10)(X2-5X-6X)=144

We move all terms to the left:

(X2-3X-10)(X2-5X-6X)-(144)=0

We add all the numbers together, and all the variables

(+X^2-3X-10)(+X^2-11X)-144=0

We move all terms containing X to the left, all other terms to the right

(+X^2-3X-10)(+X^2-11X)=144

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