(XxX)-2X+5X-10=(XxX)-12X+36

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Solution for (XxX)-2X+5X-10=(XxX)-12X+36 equation: 



(XXX)-2X+5X-10=(XXX)-12X+36

We move all terms to the left:

(XXX)-2X+5X-10-((XXX)-12X+36)=0

We add all the numbers together, and all the variables

XXX-2X+5X-(-12X+XXX+36)-10=0

We add all the numbers together, and all the variables

3X+XXX-(-12X+XXX+36)-10=0

We get rid of parentheses

3X+XXX+12X-XXX-36-10=0

We add all the numbers together, and all the variables

15X+XXX-XXX-46=0

We move all terms containing X to the left, all other terms to the right

15X+XXX-XXX=46

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