(Xy=.42)(x+y=1.3)

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Solution for (Xy=.42)(x+y=1.3) equation: 


javax.servlet.ServletException: BeanUtils.populate
	org.apache.struts.util.RequestUtils.populate(RequestUtils.java:497)
	org.apache.struts.action.RequestProcessor.processPopulate(RequestProcessor.java:798)
	org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:205)
	org.apache.struts.action.ActionServlet.process(ActionServlet.java:1164)
	org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:397)
	javax.servlet.http.HttpServlet.service(HttpServlet.java:689)
	javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
	org.tuckey.web.filters.urlrewrite.RuleChain.handleRewrite(RuleChain.java:176)
	org.tuckey.web.filters.urlrewrite.RuleChain.doRules(RuleChain.java:145)
	org.tuckey.web.filters.urlrewrite.UrlRewriter.processRequest(UrlRewriter.java:92)
	org.tuckey.web.filters.urlrewrite.UrlRewriteFilter.doFilter(UrlRewriteFilter.java:381)

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