(Y+1)/2-(y)/3=-1/3

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Solution for (Y+1)/2-(y)/3=-1/3 equation: 


x in (-oo:+oo)

(Y+1)/2-(y/3) = -1/3 // + -1/3

(Y+1)/2-(y/3)-(-1/3) = 0

(Y+1)/2-(y/3)+1/3 = 0

(Y+1)/2-y/3+1/3 = 0

(3*(Y+1))/(2*3)+(2*(-y))/(2*3)+(1*2)/(2*3) = 0

3*(Y+1)+2*(-y)+1*2 = 0

3*Y-2*y+2+3 = 0

3*Y-2*y+5 = 0

(3*Y-2*y+5)/(2*3) = 0

(3*Y-2*y+5)/(2*3) = 0 // * 2*3

3*Y-2*y+5 = 0

x belongs to the empty set

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