(Y+2)+(3Y-4)=18

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Solution for (Y+2)+(3Y-4)=18 equation: 


Simplifying
(Y + 2) + (3Y + -4) = 18

Reorder the terms:
(2 + Y) + (3Y + -4) = 18

Remove parenthesis around (2 + Y)
2 + Y + (3Y + -4) = 18

Reorder the terms:
2 + Y + (-4 + 3Y) = 18

Remove parenthesis around (-4 + 3Y)
2 + Y + -4 + 3Y = 18

Reorder the terms:
2 + -4 + Y + 3Y = 18

Combine like terms: 2 + -4 = -2
-2 + Y + 3Y = 18

Combine like terms: Y + 3Y = 4Y
-2 + 4Y = 18

Solving
-2 + 4Y = 18

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 4Y = 18 + 2

Combine like terms: -2 + 2 = 0
0 + 4Y = 18 + 2
4Y = 18 + 2

Combine like terms: 18 + 2 = 20
4Y = 20

Divide each side by '4'.
Y = 5

Simplifying
Y = 5

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