(Y+3)/2=(y-4)/3

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Solution for (Y+3)/2=(y-4)/3 equation:



(+3)/2=(Y-4)/3
We move all terms to the left:
(+3)/2-((Y-4)/3)=0
We add all the numbers together, and all the variables
-((Y-4)/3)+3/2=0
We calculate fractions
(-((Y-4)*2)/()+()/()=0
We calculate terms in parentheses: +(-((Y-4)*2)/()+()/(), so:
-((Y-4)*2)/()+()/(
We add all the numbers together, and all the variables
-((Y-4)*2)/()+1
We multiply all the terms by the denominator
-((Y-4)*2)+1*()
We calculate terms in parentheses: -((Y-4)*2), so:
(Y-4)*2
We multiply parentheses
2Y-8
Back to the equation:
-(2Y-8)
We add all the numbers together, and all the variables
-(2Y-8)
We get rid of parentheses
-2Y+8
Back to the equation:
+(-2Y+8)
We get rid of parentheses
-2Y+8=0
We move all terms containing Y to the left, all other terms to the right
-2Y=-8
Y=-8/-2
Y=+4

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