(Y-2)+2=2(3y-5)

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Solution for (Y-2)+2=2(3y-5) equation: 



(-2)+2=2(3Y-5)

We move all terms to the left:

(-2)+2-(2(3Y-5))=0

We add all the numbers together, and all the variables

-(2(3Y-5))=0



We calculate terms in parentheses: -(2(3Y-5)), so:

2(3Y-5)

We multiply parentheses

6Y-10

Back to the equation:

-(6Y-10)



We get rid of parentheses

-6Y+10=0

We move all terms containing Y to the left, all other terms to the right

-6Y=-10

Y=-10/-6

Y=1+2/3

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