(Y-3)/2=4y-12

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Solution for (Y-3)/2=4y-12 equation: 


x in (-oo:+oo)

(Y-3)/2 = 4*y-12 // - 4*y-12

(Y-3)/2-(4*y)+12 = 0

(Y-3)/2-4*y+12 = 0

(Y-3)/2+(-4*2*y)/2+(2*12)/2 = 0

Y-4*2*y+2*12-3 = 0

Y-8*y-3+24 = 0

Y-8*y+21 = 0

(Y-8*y+21)/2 = 0

(Y-8*y+21)/2 = 0 // * 2

Y-8*y+21 = 0

x belongs to the empty set

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