(Y/2)+(y/6)=(10/9)

Solution for (Y/2)+(y/6)=(10/9) equation:

(/2)+(Y/6)=(10/9)

We move all terms to the left:

(/2)+(Y/6)-((10/9))=0

We add all the numbers together, and all the variables

(+Y/6)+(+/2)-((+10/9))=0

We get rid of parentheses

Y/6+/2-((+10/9))=0

We calculate fractions


162Y^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

162Y^2/()+2=0

We multiply all the terms by the denominator


162Y^2+2*()=0

We add all the numbers together, and all the variables

162Y^2=0

a = 162; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·162·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{324}=0$