(Z+6)(z+7)=2(z+1)

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Solution for (Z+6)(z+7)=2(z+1) equation: 



(+6)(Z+7)=2(Z+1)

We move all terms to the left:

(+6)(Z+7)-(2(Z+1))=0

We add all the numbers together, and all the variables

6(Z+7)-(2(Z+1))=0

We multiply parentheses

6Z-(2(Z+1))+42=0



We calculate terms in parentheses: -(2(Z+1)), so:

2(Z+1)

We multiply parentheses

2Z+2

Back to the equation:

-(2Z+2)



We get rid of parentheses

6Z-2Z-2+42=0

We add all the numbers together, and all the variables

4Z+40=0

We move all terms containing Z to the left, all other terms to the right

4Z=-40

Z=-40/4

Z=-10

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