(Z-7)2/3=5

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Solution for (Z-7)2/3=5 equation: 


Z in (-oo:+oo)

((Z-7)^2)/3 = 5 // - 5

((Z-7)^2)/3-5 = 0

((Z-7)^2)/3+(-5*3)/3 = 0

(Z-7)^2-5*3 = 0

Z^2-14*Z+34 = 0

Z^2-14*Z+34 = 0

Z^2-14*Z+34 = 0

DELTA = (-14)^2-(1*4*34)

DELTA = 60

DELTA > 0

Z = (60^(1/2)+14)/(1*2) or Z = (14-60^(1/2))/(1*2)

Z = (2*15^(1/2)+14)/2 or Z = (14-2*15^(1/2))/2

(Z-((14-2*15^(1/2))/2))*(Z-((2*15^(1/2)+14)/2)) = 0

((Z-((14-2*15^(1/2))/2))*(Z-((2*15^(1/2)+14)/2)))/3 = 0

((Z-((14-2*15^(1/2))/2))*(Z-((2*15^(1/2)+14)/2)))/3 = 0 // * 3

(Z-((14-2*15^(1/2))/2))*(Z-((2*15^(1/2)+14)/2)) = 0

( Z-((14-2*15^(1/2))/2) )

Z-((14-2*15^(1/2))/2) = 0 // + (14-2*15^(1/2))/2

Z = (14-2*15^(1/2))/2

( Z-((2*15^(1/2)+14)/2) )

Z-((2*15^(1/2)+14)/2) = 0 // + (2*15^(1/2)+14)/2

Z = (2*15^(1/2)+14)/2

Z in { (14-2*15^(1/2))/2, (2*15^(1/2)+14)/2 }

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