(a*2c)+(b*2c)+c=180

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Solution for (a*2c)+(b*2c)+c=180 equation: 


Simplifying
(a * 2c) + (b * 2c) + c = 180

Reorder the terms for easier multiplication:
(2a * c) + (b * 2c) + c = 180

Multiply a * c
(2ac) + (b * 2c) + c = 180

Reorder the terms for easier multiplication:
(2ac) + (2b * c) + c = 180

Multiply b * c
(2ac) + (2bc) + c = 180

Solving
(2ac) + (2bc) + c = 180

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '(-2bc)' to each side of the equation.
(2ac) + (2bc) + (-2bc) + c = 180 + (-2bc)

Combine like terms: (2bc) + (-2bc) = 0
(2ac) + 0 + c = 180 + (-2bc)
(2ac) + c = 180 + (-2bc)

Add '-1c' to each side of the equation.
(2ac) + c + -1c = 180 + (-2bc) + -1c

Combine like terms: c + -1c = 0
(2ac) + 0 = 180 + (-2bc) + -1c
(2ac) = 180 + (-2bc) + -1c

Divide each side by '(2c)'.
a = 90c-1 + (-1b) + -0.5

Simplifying
a = 90c-1 + (-1b) + -0.5

Reorder the terms:
a = -0.5 + (-1b) + 90c-1

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