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(a+1)(a+2)=a2+3a+2
We move all terms to the left:
(a+1)(a+2)-(a2+3a+2)=0
We add all the numbers together, and all the variables
-(+a^2+3a+2)+(a+1)(a+2)=0
We get rid of parentheses
-a^2-3a+(a+1)(a+2)-2=0
We multiply parentheses ..
-a^2+(+a^2+2a+a+2)-3a-2=0
We add all the numbers together, and all the variables
-1a^2+(+a^2+2a+a+2)-3a-2=0
We get rid of parentheses
-1a^2+a^2+2a+a-3a+2-2=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0
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