(a+1)*(a+2)=

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Solution for (a+1)*(a+2)= equation:


Simplifying
(a + 1)(a + 2) = 0

Reorder the terms:
(1 + a)(a + 2) = 0

Reorder the terms:
(1 + a)(2 + a) = 0

Multiply (1 + a) * (2 + a)
(1(2 + a) + a(2 + a)) = 0
((2 * 1 + a * 1) + a(2 + a)) = 0
((2 + 1a) + a(2 + a)) = 0
(2 + 1a + (2 * a + a * a)) = 0
(2 + 1a + (2a + a2)) = 0

Combine like terms: 1a + 2a = 3a
(2 + 3a + a2) = 0

Solving
2 + 3a + a2 = 0

Solving for variable 'a'.

Factor a trinomial.
(2 + a)(1 + a) = 0

Subproblem 1

Set the factor '(2 + a)' equal to zero and attempt to solve: Simplifying 2 + a = 0 Solving 2 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + a = 0 + -2 Combine like terms: 2 + -2 = 0 0 + a = 0 + -2 a = 0 + -2 Combine like terms: 0 + -2 = -2 a = -2 Simplifying a = -2

Subproblem 2

Set the factor '(1 + a)' equal to zero and attempt to solve: Simplifying 1 + a = 0 Solving 1 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + a = 0 + -1 Combine like terms: 1 + -1 = 0 0 + a = 0 + -1 a = 0 + -1 Combine like terms: 0 + -1 = -1 a = -1 Simplifying a = -1

Solution

a = {-2, -1}

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