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(a+10)(a-10=)
We move all terms to the left:
(a+10)(a-10-())=0
We calculate terms in parentheses: +(a+10)(a-10-()), so:We multiply parentheses
a+10)(a-10-()
We add all the numbers together, and all the variables
a+10)(a
Back to the equation:
+(a+10)(a)
a^2+10a=0
a = 1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·1·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*1}=\frac{-20}{2} =-10 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*1}=\frac{0}{2} =0 $
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