(a+2)(2a+4)=

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Solution for (a+2)(2a+4)= equation:


Simplifying
(a + 2)(2a + 4) = 0

Reorder the terms:
(2 + a)(2a + 4) = 0

Reorder the terms:
(2 + a)(4 + 2a) = 0

Multiply (2 + a) * (4 + 2a)
(2(4 + 2a) + a(4 + 2a)) = 0
((4 * 2 + 2a * 2) + a(4 + 2a)) = 0
((8 + 4a) + a(4 + 2a)) = 0
(8 + 4a + (4 * a + 2a * a)) = 0
(8 + 4a + (4a + 2a2)) = 0

Combine like terms: 4a + 4a = 8a
(8 + 8a + 2a2) = 0

Solving
8 + 8a + 2a2 = 0

Solving for variable 'a'.

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + 4a + a2) = 0

Factor a trinomial.
2((2 + a)(2 + a)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + a)' equal to zero and attempt to solve: Simplifying 2 + a = 0 Solving 2 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + a = 0 + -2 Combine like terms: 2 + -2 = 0 0 + a = 0 + -2 a = 0 + -2 Combine like terms: 0 + -2 = -2 a = -2 Simplifying a = -2

Subproblem 2

Set the factor '(2 + a)' equal to zero and attempt to solve: Simplifying 2 + a = 0 Solving 2 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + a = 0 + -2 Combine like terms: 2 + -2 = 0 0 + a = 0 + -2 a = 0 + -2 Combine like terms: 0 + -2 = -2 a = -2 Simplifying a = -2

Solution

a = {-2, -2}

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