(a+2)(2b+3c)=

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Solution for (a+2)(2b+3c)= equation:


Simplifying
(a + 2)(2b + 3c) = 0

Reorder the terms:
(2 + a)(2b + 3c) = 0

Multiply (2 + a) * (2b + 3c)
(2(2b + 3c) + a(2b + 3c)) = 0
((2b * 2 + 3c * 2) + a(2b + 3c)) = 0
((4b + 6c) + a(2b + 3c)) = 0
(4b + 6c + (2b * a + 3c * a)) = 0
(4b + 6c + (2ab + 3ac)) = 0

Reorder the terms:
(2ab + 3ac + 4b + 6c) = 0
(2ab + 3ac + 4b + 6c) = 0

Solving
2ab + 3ac + 4b + 6c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4b' to each side of the equation.
2ab + 3ac + 4b + -4b + 6c = 0 + -4b

Combine like terms: 4b + -4b = 0
2ab + 3ac + 0 + 6c = 0 + -4b
2ab + 3ac + 6c = 0 + -4b
Remove the zero:
2ab + 3ac + 6c = -4b

Add '-6c' to each side of the equation.
2ab + 3ac + 6c + -6c = -4b + -6c

Combine like terms: 6c + -6c = 0
2ab + 3ac + 0 = -4b + -6c
2ab + 3ac = -4b + -6c

Reorder the terms:
2ab + 3ac + 4b + 6c = -4b + 4b + -6c + 6c

Combine like terms: -4b + 4b = 0
2ab + 3ac + 4b + 6c = 0 + -6c + 6c
2ab + 3ac + 4b + 6c = -6c + 6c

Combine like terms: -6c + 6c = 0
2ab + 3ac + 4b + 6c = 0

The solution to this equation could not be determined.

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