(a+2)(a-1)=-4

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Solution for (a+2)(a-1)=-4 equation: 



(a+2)(a-1)=-4

We move all terms to the left:

(a+2)(a-1)-(-4)=0

We add all the numbers together, and all the variables

(a+2)(a-1)+4=0

We multiply parentheses ..

(+a^2-1a+2a-2)+4=0

We get rid of parentheses

a^2-1a+2a-2+4=0

We add all the numbers together, and all the variables

a^2+a+2=0

a = 1; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·1·2
Δ = -7
Delta is less than zero, so there is no solution for the equation

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