(a+2)3+4(2a-1)=13

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Solution for (a+2)3+4(2a-1)=13 equation: 



(a+2)3+4(2a-1)=13

We move all terms to the left:

(a+2)3+4(2a-1)-(13)=0

We multiply parentheses

3a+8a+6-4-13=0

We add all the numbers together, and all the variables

11a-11=0

We move all terms containing a to the left, all other terms to the right

11a=11

a=11/11

a=1

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