(a+2b)+3c=a+(2b+3c)

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Solution for (a+2b)+3c=a+(2b+3c) equation:


Simplifying
(a + 2b) + 3c = a + (2b + 3c)

Remove parenthesis around (a + 2b)
a + 2b + 3c = a + (2b + 3c)

Remove parenthesis around (2b + 3c)
a + 2b + 3c = a + 2b + 3c

Add '-1a' to each side of the equation.
a + 2b + -1a + 3c = a + 2b + -1a + 3c

Reorder the terms:
a + -1a + 2b + 3c = a + 2b + -1a + 3c

Combine like terms: a + -1a = 0
0 + 2b + 3c = a + 2b + -1a + 3c
2b + 3c = a + 2b + -1a + 3c

Reorder the terms:
2b + 3c = a + -1a + 2b + 3c

Combine like terms: a + -1a = 0
2b + 3c = 0 + 2b + 3c
2b + 3c = 2b + 3c

Add '-2b' to each side of the equation.
2b + -2b + 3c = 2b + -2b + 3c

Combine like terms: 2b + -2b = 0
0 + 3c = 2b + -2b + 3c
3c = 2b + -2b + 3c

Combine like terms: 2b + -2b = 0
3c = 0 + 3c
3c = 3c

Add '-3c' to each side of the equation.
3c + -3c = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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