(a+2b)/4+4a

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Solution for (a+2b)/4+4a equation: 


x in (-oo:+oo)

(a+2*b)/4+4*a = 0

(a+2*b)/4+(4*4*a)/4 = 0

a+4*4*a+2*b = 0

17*a+2*b = 0

(17*a+2*b)/4 = 0

(17*a+2*b)/4 = 0 // * 4

17*a+2*b = 0

x belongs to the empty set

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