(a+3)(a+4)=-10(a-5)

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Solution for (a+3)(a+4)=-10(a-5) equation:


Simplifying
(a + 3)(a + 4) = -10(a + -5)

Reorder the terms:
(3 + a)(a + 4) = -10(a + -5)

Reorder the terms:
(3 + a)(4 + a) = -10(a + -5)

Multiply (3 + a) * (4 + a)
(3(4 + a) + a(4 + a)) = -10(a + -5)
((4 * 3 + a * 3) + a(4 + a)) = -10(a + -5)
((12 + 3a) + a(4 + a)) = -10(a + -5)
(12 + 3a + (4 * a + a * a)) = -10(a + -5)
(12 + 3a + (4a + a2)) = -10(a + -5)

Combine like terms: 3a + 4a = 7a
(12 + 7a + a2) = -10(a + -5)

Reorder the terms:
12 + 7a + a2 = -10(-5 + a)
12 + 7a + a2 = (-5 * -10 + a * -10)
12 + 7a + a2 = (50 + -10a)

Solving
12 + 7a + a2 = 50 + -10a

Solving for variable 'a'.

Reorder the terms:
12 + -50 + 7a + 10a + a2 = 50 + -10a + -50 + 10a

Combine like terms: 12 + -50 = -38
-38 + 7a + 10a + a2 = 50 + -10a + -50 + 10a

Combine like terms: 7a + 10a = 17a
-38 + 17a + a2 = 50 + -10a + -50 + 10a

Reorder the terms:
-38 + 17a + a2 = 50 + -50 + -10a + 10a

Combine like terms: 50 + -50 = 0
-38 + 17a + a2 = 0 + -10a + 10a
-38 + 17a + a2 = -10a + 10a

Combine like terms: -10a + 10a = 0
-38 + 17a + a2 = 0

Factor a trinomial.
(-19 + -1a)(2 + -1a) = 0

Subproblem 1

Set the factor '(-19 + -1a)' equal to zero and attempt to solve: Simplifying -19 + -1a = 0 Solving -19 + -1a = 0 Move all terms containing a to the left, all other terms to the right. Add '19' to each side of the equation. -19 + 19 + -1a = 0 + 19 Combine like terms: -19 + 19 = 0 0 + -1a = 0 + 19 -1a = 0 + 19 Combine like terms: 0 + 19 = 19 -1a = 19 Divide each side by '-1'. a = -19 Simplifying a = -19

Subproblem 2

Set the factor '(2 + -1a)' equal to zero and attempt to solve: Simplifying 2 + -1a = 0 Solving 2 + -1a = 0 Move all terms containing a to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1a = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1a = 0 + -2 -1a = 0 + -2 Combine like terms: 0 + -2 = -2 -1a = -2 Divide each side by '-1'. a = 2 Simplifying a = 2

Solution

a = {-19, 2}

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