(a+3)(a-3)(a+4)=0

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Solution for (a+3)(a-3)(a+4)=0 equation: 


Simplifying
(a + 3)(a + -3)(a + 4) = 0

Reorder the terms:
(3 + a)(a + -3)(a + 4) = 0

Reorder the terms:
(3 + a)(-3 + a)(a + 4) = 0

Reorder the terms:
(3 + a)(-3 + a)(4 + a) = 0

Multiply (3 + a) * (-3 + a)
(3(-3 + a) + a(-3 + a))(4 + a) = 0
((-3 * 3 + a * 3) + a(-3 + a))(4 + a) = 0
((-9 + 3a) + a(-3 + a))(4 + a) = 0
(-9 + 3a + (-3 * a + a * a))(4 + a) = 0
(-9 + 3a + (-3a + a2))(4 + a) = 0

Combine like terms: 3a + -3a = 0
(-9 + 0 + a2)(4 + a) = 0
(-9 + a2)(4 + a) = 0

Multiply (-9 + a2) * (4 + a)
(-9(4 + a) + a2(4 + a)) = 0
((4 * -9 + a * -9) + a2(4 + a)) = 0
((-36 + -9a) + a2(4 + a)) = 0
(-36 + -9a + (4 * a2 + a * a2)) = 0
(-36 + -9a + (4a2 + a3)) = 0
(-36 + -9a + 4a2 + a3) = 0

Solving
-36 + -9a + 4a2 + a3 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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