(a+3)/2;a=5

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Solution for (a+3)/2;a=5 equation: 



(a+3)/2a=5

We move all terms to the left:

(a+3)/2a-(5)=0



Domain of the equation: 2a!=0

a!=0/2

a!=0

a∈R



We multiply all the terms by the denominator


(a+3)-5*2a=0

Wy multiply elements

(a+3)-10a=0

We get rid of parentheses

a-10a+3=0

We add all the numbers together, and all the variables

-9a+3=0

We move all terms containing a to the left, all other terms to the right

-9a=-3

a=-3/-9

a=1/3

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