(a+4)+2bi=6-5ib

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Solution for (a+4)+2bi=6-5ib equation:


Simplifying
(a + 4) + 2bi = 6 + -5ib

Reorder the terms:
(4 + a) + 2bi = 6 + -5ib

Remove parenthesis around (4 + a)
4 + a + 2bi = 6 + -5ib

Solving
4 + a + 2bi = 6 + -5bi

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + a + -4 + 2bi = 6 + -4 + -5bi

Reorder the terms:
4 + -4 + a + 2bi = 6 + -4 + -5bi

Combine like terms: 4 + -4 = 0
0 + a + 2bi = 6 + -4 + -5bi
a + 2bi = 6 + -4 + -5bi

Combine like terms: 6 + -4 = 2
a + 2bi = 2 + -5bi

Add '-2bi' to each side of the equation.
a + 2bi + -2bi = 2 + -5bi + -2bi

Combine like terms: 2bi + -2bi = 0
a + 0 = 2 + -5bi + -2bi
a = 2 + -5bi + -2bi

Combine like terms: -5bi + -2bi = -7bi
a = 2 + -7bi

Simplifying
a = 2 + -7bi

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