(a+4c)(a-4c)=

Solution for (a+4c)(a-4c)= equation:

Simplifying
(a + 4c)(a + -4c) = 0

Multiply (a + 4c) * (a + -4c)
(a(a + -4c) + 4c * (a + -4c)) = 0
((a * a + -4c * a) + 4c * (a + -4c)) = 0

Reorder the terms:
((-4ac + a2) + 4c * (a + -4c)) = 0
((-4ac + a2) + 4c * (a + -4c)) = 0
(-4ac + a2 + (a * 4c + -4c * 4c)) = 0
(-4ac + a2 + (4ac + -16c2)) = 0

Reorder the terms:
(-4ac + 4ac + a2 + -16c2) = 0

Combine like terms: -4ac + 4ac = 0
(0 + a2 + -16c2) = 0
(a2 + -16c2) = 0

Solving
a2 + -16c2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '16c2' to each side of the equation.
a2 + -16c2 + 16c2 = 0 + 16c2

Combine like terms: -16c2 + 16c2 = 0
a2 + 0 = 0 + 16c2
a2 = 0 + 16c2
Remove the zero:
a2 = 16c2

Simplifying
a2 = 16c2

Take the square root of each side:
a = {-4c, 4c}