(a+5+a-5)+16=(a-3)

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Solution for (a+5+a-5)+16=(a-3) equation: 



(a+5+a-5)+16=(a-3)

We move all terms to the left:

(a+5+a-5)+16-((a-3))=0

We add all the numbers together, and all the variables

(+2a)-((a-3))+16=0

We get rid of parentheses

2a-((a-3))+16=0



We calculate terms in parentheses: -((a-3)), so:

(a-3)

We get rid of parentheses

a-3

Back to the equation:

-(a-3)



We get rid of parentheses

2a-a+3+16=0

We add all the numbers together, and all the variables

a+19=0

We move all terms containing a to the left, all other terms to the right

a=-19

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