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(a+6)(7a-4)=0
We multiply parentheses ..
(+7a^2-4a+42a-24)=0
We get rid of parentheses
7a^2-4a+42a-24=0
We add all the numbers together, and all the variables
7a^2+38a-24=0
a = 7; b = 38; c = -24;
Δ = b2-4ac
Δ = 382-4·7·(-24)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-46}{2*7}=\frac{-84}{14} =-6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+46}{2*7}=\frac{8}{14} =4/7 $
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