(a+7)/3=(a-3)/5

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Solution for (a+7)/3=(a-3)/5 equation: 



(a+7)/3=(a-3)/5

We move all terms to the left:

(a+7)/3-((a-3)/5)=0

We calculate fractions


a/()+(-((a-3)*3)/()=0



We calculate terms in parentheses: +(-((a-3)*3)/(), so:

-((a-3)*3)/(

We multiply all the terms by the denominator


-((a-3)*3)



We calculate terms in parentheses: -((a-3)*3), so:

(a-3)*3

We multiply parentheses

3a-9

Back to the equation:

-(3a-9)



We get rid of parentheses

-3a+9

Back to the equation:

+(-3a+9)



We get rid of parentheses

a/()-3a+9=0

We multiply all the terms by the denominator


a-3a*()+9*()=0

We add all the numbers together, and all the variables

a-3a*()=0

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