(a+b)(b+c)(a+c)=2013

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Solution for (a+b)(b+c)(a+c)=2013 equation: 


Simplifying
(a + b)(b + c)(a + c) = 2013

Multiply (a + b) * (b + c)
(a(b + c) + b(b + c))(a + c) = 2013
((b * a + c * a) + b(b + c))(a + c) = 2013
((ab + ac) + b(b + c))(a + c) = 2013
(ab + ac + (b * b + c * b))(a + c) = 2013

Reorder the terms:
(ab + ac + (bc + b2))(a + c) = 2013
(ab + ac + (bc + b2))(a + c) = 2013
(ab + ac + bc + b2)(a + c) = 2013

Multiply (ab + ac + bc + b2) * (a + c)
(ab(a + c) + ac(a + c) + bc(a + c) + b2(a + c)) = 2013
((a * ab + c * ab) + ac(a + c) + bc(a + c) + b2(a + c)) = 2013

Reorder the terms:
((abc + a2b) + ac(a + c) + bc(a + c) + b2(a + c)) = 2013
((abc + a2b) + ac(a + c) + bc(a + c) + b2(a + c)) = 2013
(abc + a2b + (a * ac + c * ac) + bc(a + c) + b2(a + c)) = 2013

Reorder the terms:
(abc + a2b + (ac2 + a2c) + bc(a + c) + b2(a + c)) = 2013
(abc + a2b + (ac2 + a2c) + bc(a + c) + b2(a + c)) = 2013
(abc + a2b + ac2 + a2c + (a * bc + c * bc) + b2(a + c)) = 2013
(abc + a2b + ac2 + a2c + (abc + bc2) + b2(a + c)) = 2013
(abc + a2b + ac2 + a2c + abc + bc2 + (a * b2 + c * b2)) = 2013
(abc + a2b + ac2 + a2c + abc + bc2 + (ab2 + b2c)) = 2013

Reorder the terms:
(abc + abc + ab2 + ac2 + a2b + a2c + bc2 + b2c) = 2013

Combine like terms: abc + abc = 2abc
(2abc + ab2 + ac2 + a2b + a2c + bc2 + b2c) = 2013

Solving
2abc + ab2 + ac2 + a2b + a2c + bc2 + b2c = 2013

Solving for variable 'a'.

Reorder the terms:
-2013 + 2abc + ab2 + ac2 + a2b + a2c + bc2 + b2c = 2013 + -2013

Combine like terms: 2013 + -2013 = 0
-2013 + 2abc + ab2 + ac2 + a2b + a2c + bc2 + b2c = 0

The solution to this equation could not be determined.

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