(a+b-c)(a+b+c)=

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Solution for (a+b-c)(a+b+c)= equation:


Simplifying
(a + b + -1c)(a + b + c) = 0

Multiply (a + b + -1c) * (a + b + c)
(a(a + b + c) + b(a + b + c) + -1c * (a + b + c)) = 0
((a * a + b * a + c * a) + b(a + b + c) + -1c * (a + b + c)) = 0

Reorder the terms:
((ab + ac + a2) + b(a + b + c) + -1c * (a + b + c)) = 0
((ab + ac + a2) + b(a + b + c) + -1c * (a + b + c)) = 0
(ab + ac + a2 + (a * b + b * b + c * b) + -1c * (a + b + c)) = 0

Reorder the terms:
(ab + ac + a2 + (ab + bc + b2) + -1c * (a + b + c)) = 0
(ab + ac + a2 + (ab + bc + b2) + -1c * (a + b + c)) = 0
(ab + ac + a2 + ab + bc + b2 + (a * -1c + b * -1c + c * -1c)) = 0
(ab + ac + a2 + ab + bc + b2 + (-1ac + -1bc + -1c2)) = 0

Reorder the terms:
(ab + ab + ac + -1ac + a2 + bc + -1bc + b2 + -1c2) = 0

Combine like terms: ab + ab = 2ab
(2ab + ac + -1ac + a2 + bc + -1bc + b2 + -1c2) = 0

Combine like terms: ac + -1ac = 0
(2ab + 0 + a2 + bc + -1bc + b2 + -1c2) = 0
(2ab + a2 + bc + -1bc + b2 + -1c2) = 0

Combine like terms: bc + -1bc = 0
(2ab + a2 + 0 + b2 + -1c2) = 0
(2ab + a2 + b2 + -1c2) = 0

Solving
2ab + a2 + b2 + -1c2 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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