(a+bc)+cb+ab+ac-3(ab-cb-ba+bc)=

Solution for (a+bc)+cb+ab+ac-3(ab-cb-ba+bc)= equation:

Simplifying
(a + bc) + cb + ab + ac + -3(ab + -1cb + -1ba + bc) = 0

Remove parenthesis around (a + bc)
a + bc + cb + ab + ac + -3(ab + -1cb + -1ba + bc) = 0

Reorder the terms:
a + bc + bc + ab + ac + -3(ab + -1ab + -1bc + bc) = 0

Combine like terms: ab + -1ab = 0
a + bc + bc + ab + ac + -3(0 + -1bc + bc) = 0
a + bc + bc + ab + ac + -3(-1bc + bc) = 0

Combine like terms: -1bc + bc = 0
a + bc + bc + ab + ac + -3(0) = 0

Multiply -3 * 0
a + bc + bc + ab + ac + 0 = 0

Anything times zero is zero.
a + bc + bc + ab + ac + 0 = 0

Reorder the terms:
0 + a + ab + ac + bc + bc = 0
Remove the zero:
a + ab + ac + bc + bc = 0

Combine like terms: bc + bc = 2bc
a + ab + ac + 2bc = 0

Solving
a + ab + ac + 2bc = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2bc' to each side of the equation.
a + ab + ac + 2bc + -2bc = 0 + -2bc

Combine like terms: 2bc + -2bc = 0
a + ab + ac + 0 = 0 + -2bc
a + ab + ac = 0 + -2bc
Remove the zero:
a + ab + ac = -2bc

Combine like terms: -2bc + 2bc = 0
a + ab + ac + 2bc = 0

The solution to this equation could not be determined.