(a+c)(a-c)=

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Solution for (a+c)(a-c)= equation:


Simplifying
(a + c)(a + -1c) = 0

Multiply (a + c) * (a + -1c)
(a(a + -1c) + c(a + -1c)) = 0
((a * a + -1c * a) + c(a + -1c)) = 0

Reorder the terms:
((-1ac + a2) + c(a + -1c)) = 0
((-1ac + a2) + c(a + -1c)) = 0
(-1ac + a2 + (a * c + -1c * c)) = 0
(-1ac + a2 + (ac + -1c2)) = 0

Reorder the terms:
(-1ac + ac + a2 + -1c2) = 0

Combine like terms: -1ac + ac = 0
(0 + a2 + -1c2) = 0
(a2 + -1c2) = 0

Solving
a2 + -1c2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'c2' to each side of the equation.
a2 + -1c2 + c2 = 0 + c2

Combine like terms: -1c2 + c2 = 0
a2 + 0 = 0 + c2
a2 = 0 + c2
Remove the zero:
a2 = c2

Simplifying
a2 = c2

Take the square root of each side:
a = {-1c, c}

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