(a-3)-5(a+2)=2a

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Solution for (a-3)-5(a+2)=2a equation: 



(a-3)-5(a+2)=2a

We move all terms to the left:

(a-3)-5(a+2)-(2a)=0

We add all the numbers together, and all the variables

-2a+(a-3)-5(a+2)=0

We multiply parentheses

-2a+(a-3)-5a-10=0

We get rid of parentheses

-2a+a-5a-3-10=0

We add all the numbers together, and all the variables

-6a-13=0

We move all terms containing a to the left, all other terms to the right

-6a=13

a=13/-6

a=-2+1/6

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