(a-3)/(3a+2)=1/5

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Solution for (a-3)/(3a+2)=1/5 equation:


D( a )

3*a+2 = 0

3*a+2 = 0

3*a+2 = 0

3*a+2 = 0 // - 2

3*a = -2 // : 3

a = -2/3

a in (-oo:-2/3) U (-2/3:+oo)

(a-3)/(3*a+2) = 1/5 // - 1/5

(a-3)/(3*a+2)-(1/5) = 0

(a-3)/(3*a+2)-1/5 = 0

(5*(a-3))/(5*(3*a+2))+(-1*(3*a+2))/(5*(3*a+2)) = 0

5*(a-3)-1*(3*a+2) = 0

2*a-17 = 0

(2*a-17)/(5*(3*a+2)) = 0

(2*a-17)/(5*(3*a+2)) = 0 // * 5*(3*a+2)

2*a-17 = 0

2*a-17 = 0 // + 17

2*a = 17 // : 2

a = 17/2

a = 17/2

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