(a-3)=8a-(4a-12)

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Solution for (a-3)=8a-(4a-12) equation: 



(a-3)=8a-(4a-12)

We move all terms to the left:

(a-3)-(8a-(4a-12))=0

We get rid of parentheses

a-(8a-(4a-12))-3=0



We calculate terms in parentheses: -(8a-(4a-12)), so:

8a-(4a-12)

We get rid of parentheses

8a-4a+12

We add all the numbers together, and all the variables

4a+12

Back to the equation:

-(4a+12)



We get rid of parentheses

a-4a-12-3=0

We add all the numbers together, and all the variables

-3a-15=0

We move all terms containing a to the left, all other terms to the right

-3a=15

a=15/-3

a=-5

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